Question

CUM SE FACE
\frac{X+1}{X+2} \geq 0
VA ROG REPEDEEE

Answer 1

$\frac{X+1}{X+2} \geq 0$
1. [tex] \left \{ {{x=1 \geq 0} \atop {x+2\ \textgreater \ 0}} \right. = \left \{ {{x \geq -1} \atop {x\ \textgreater \ -2}} \right. = x∈[-1,+∞) [/tex]
2. $\left \{ {{x=1 \leq 0} \atop {x+2\ \textless \ 0}} \right. = \left \{ {{x \leq -1} \atop {x\ \textless \ -2}} \right.= x ∈ ( -∞ ,-2)$
Rs: x∈(-∞,-2)∪[-1,+∞)