Question

Cum se face urmatorul exercitiu?
4+3i/3-4i - 2+i/1-2i

Answer 1

$\frac{4+3i}{3-4i}+ \frac{2+i}{1-2i} = \frac{(4+3i)(3+4i)}{(3-4i)(3+4i)}+ \frac{(2+i)(1+2i)}{(1-2i)(1+2i)}= \frac{12+16i+9i-12}{9+12i-12i+16} + \frac{2+4i+i-2}{1+2i-2i+4}= \\ \frac{25i}{25}+ \frac{5i}{5}=i+i=2i$