Question

Cum se face? (x+2) la patrat-4x

Answer 1

(x+2)(x+2)-4x=0 ⇒ x²+4x+4-4x=0 ⇒ x²+4=0 ⇒ x²=4 ⇒ x=2

S={2}

Answer 2

(x+2)^2-4x=0... x^2+4x+4-4x=0... x^2+4=0...
∆=b^2-4ac
∆=0^2-4•1•4
∆=-16

Cum delta < 0 ecuatia nu admite solutii reale, dar admite solutii complexe:
x1,2=(-b+ sau - i√-∆)/2a

x1=(i√16)/2...x1=4i/2...x1=2i

x2=(-i√16)/2...x2=-4i/2...x2=-2i

S={-2i,2i} fiind solutii complexe.