Question

Cum se facee?!!!! Plss. Dau coroana

Answer 1

pai doar aplici formula
[tex](x- \sqrt{3}+2 \sqrt{3})(x- \sqrt{3}-2 \sqrt{3})= (x+ \sqrt{3} )(x-3 \sqrt{3}) [/tex]

b) $(\sqrt{2} -y)^2-(\sqrt2)^2=(\sqrt2-y-\sqrt2)(\sqrt2-y+\sqrt2)=-y(2\sqrt2-y)$

c)$(\sqrt3x-1)^2-3=(\sqrt3x-1)^2-\sqrt3^2=(\sqrt3x-1-\sqrt3)(\sqrt3x-1+\sqrt3)$