Question

Cum se rezolvā:
1.2x+√25=√49
2.√100-3x=√16-6
3.√64-2x=-√4
Vā rogg multt ajutati -ma cat mai repedee..

Answer 1

1)
2x+$\sqrt{25}= \sqrt{49}$ ⇔ 2x+5=7 ⇒ x=7-5=2
2)
$\sqrt{100}-3x= \sqrt{16}-6$ ⇔ 10-3x=4-6  ⇔ 3x=12  ⇒  x=4
3)
$\sqrt{64}-2x=- \sqrt{4}$  ⇔ 8-2x=-2  ⇔  2x=10  ⇒ x=5 

Answer 2

Mor delia mor Tine-ma Mor