Question

Cum se rezolva 16 la puterea x -64=0 și 8 la puterea x - 2=0. Multumesc.

Answer 1

Salut,

$16^x-64=0,\ sau\ (2^4)^x-2^6=0,\ deci\ 2^{4x}=2^6,\ adic\breve{a}\ 4x=6,\ deci\ x=\dfrac{3}2;\\\\8^x-2=0,\ sau\ (2^3)^x-2^1=0,\ deci\ 2^{3x}=2^1,\ adic\breve{a}\ 3x=1,\ deci\ x=\dfrac{1}3.$

Green eyes.

Answer 2

16^x - 64 = 0 
16^x = 64 
(4^2)^x = 4^3 
4^2x= 4^3 
2x =3 
x = 3/2 

8^x - 2 = 0 
(2^3)^x = 2 
2^3x = 2 
3x = 1 
x = 1/3