Question

Cum se rezolva 2x2^2x(2^2)^2:[2+2^2+(2^2)^2:[(2^2)^2-2^2x2]​

Answer 1

Explicație pas cu pas:

$2 \times {2}^{2} \times { {2}^{2} }^{2} \div (2 + {2}^{2} + { {2}^{2} }^{2} \div { {2}^{2} }^{2} - {2}^{2} \times 2) = {2}^{1 + 2 + 4} \div ( {2}^{1} + {2}^{2} + {2}^{4 - 4} - {2}^{3} ) = {2}^{7} \div (2 + 4 + 1 - 8) = {2}^{7} \div ( - 1)$