Question

Cum se rezolva:
(3+√2) la 2 -12/√2

Answer 1

$\displaystyle (3+ \sqrt{2} )^2- \frac{12}{ \sqrt{2} }=3^2+2 \cdot 3 \cdot \sqrt{2} + \sqrt{2} ^2- \frac{12 \sqrt{2} }{2} = \\ \\ =9+6 \sqrt{2} +2-6 \sqrt{2} =9+2=11$