Question

cum se rezolva? (-3)la 0 +(-3) la 42 ori (-3la 23):81 la 16

Answer 1

$(-3)^0+(-3)^4^2 \cdot (-3^2^3):81^1^6=1-3^{42+23}:81^1^6= 1-3^6^5:81^1^6= \\ =1-3^6^5:(3^4)^1^6=1-3^6^5:3^6^4=1- 3^{65-64}=1-3^1=1-3=-2$

Answer 2

(-3)⁰ +(-3)⁴² × (-3²³):81¹⁶ =
=1 +3⁴²  ×(-3²³):(3⁴)¹⁶ =
=1 +3⁴²  ×[-(3)²³]:3⁶⁴ =
=1 +3⁴²  ×[-(3)⁻⁴¹] =
=1 +3⁴²  ×[-(3)⁻⁴¹ ]=
=1-3=-2