Question

Cum se rezolva
a+b+c = 68
a = c + 12
a = b x 2

Answer 1

$\it a=b\cdot2 \Rightarrow a=2b\\ \\ a=c+12 \Rightarrow c=a-12 \Rightarrow c=2b-12\\ \\ a+b+c=68 \Rightarrow 2b+b+2b-12=68 \Rightarrow 5b-12=68|_{+12} \Rightarrow \\ \\ \Rightarrow 5b=80|_{:5} \Rightarrow b=16\\ \\ a=2b=2\cdot16=32\\ \\ c=2b-12=32-12=20$

Numerele  cerute  sunt:  a = 32,  b=16,  c=20

Answer 2

Răspuns:

a+b+c=68

a=c+12=>c=a-12

a=2b=>b=a/2

²⁾a+a/2+²⁾a-²⁾12=²⁾68

2a+a+2a-24=136

5a=136+24

a=160:5=>a=32

b=32:2=>b=16

c=32-12=>c=20