Question

Cum se rezolva acest exercitiu?

Answer 1

Răspuns:

yAB= -0.25x-2.75

yBC= -0.167x-3.167

yCA= -0.5x-3.5

Ha (modul)=I((-0.167)*5-(-4)+(-3.167))/(1+0.167^2)^0.5I=0.657

Hb= 1.789

Hc=0.485

AB= ((5+3)^2+(4-2)^2)^0.5=8.246

Sabc= AB*Hc/2=8.246*.485/2=2.04

Explicație pas cu pas:

ec AB    A(-3,-2 )    B(5,-4)

                 -2=-3*m1+n1

                -4=5m1+n1

_________________

-2=8m1   =>   m1=-0.5    =>   n1= -2- 3*0.25=-2.75

dist de la un punct (ax,ay)  la  o dreapta y=mx+n

H = modul [(m*ax-ay+n)/(1+m^2)^0.5]

lungimea AB = ((xb-xa)^2+(yb-ya)^2)^0.5