Question

cum se rezolva ecuatia: 3+3*{3+3*[3+3*(3-3/y)]}=3*31

Answer 1

3+3x{3+3x[3+3x(3-3:y)]}=93
3x{3+3x[3+3x(3-3:y)]}=93-3⇒90
{3+3x[3+3x(3-3:y)]}=90:3 ⇒30
3x[3+3x(3-3:y)]=30-3 ⇒27
[3+3x(3-3:y)]=27:3 ⇒9
3x(3-3:y)=9-3 ⇒6
(3-3:y)=6:3 ⇒2
3:y=3-2
3:y=1
y=3:1
y=3