Question

cum se rezolva ecuatia asta : (3x+2)^2 = 4

Answer 1

3x+2= radical din 4
3x=4-2=2
x=2/3

Answer 2

$\displaystyle (3x+2)^2=4 \\ (3x)^2+2 \cdot 3x \cdot 2+2^2=4 \\ 9x^2+12x+4=4 \\ 9x^2+12x=4-4 \\ 9x^2+12x=0 \\ 3x(3x+4)=0 \\ 3x=0 \\ x=0 \\ 3x+4=0 \\ 3x=0-4 \\ 3x=-4 \\ x=- \frac{4}{3} \\ S=\left \{- \frac{4}{3} ;0 \right \}$