Question

cum se rezolva ex:2×{5+3×[2+3×(2+3M)]}-2=2000

Answer 1

2x{5+3x[2+3x(2+3M)]}-2=2000

2x{5+3x[2+3x(2+3M)]}=2000+2

5+3x[2+3x(2+3M)]=2002:2

3x[2+3x(2+3M)]=1001-5

2+3x(2+3M)=996:3

3x(2+3M)=332-2

2+3M=330:3

3M=110-2

M=108:3

M=36

Answer 2

2 × { 5 + 3 × [ 2 + 3 × ( 2 + 3 m ) ] } - 2 = 2 000

2 × { 5 + 3 × [ 2 + 3 × ( 2 + 3 m ) ] } = 2 000 + 2

5 + 3 × [ 2 + 3 × ( 2 + 3 m ) ] = 2002 : 2

3 × [ 2 + 3 × ( 2 + 3 m ) ] = 1001 - 5

2 + 3 × ( 2 + 3 m ) = 996 : 3

3 × ( 2 + 3 m ) = 332 - 2

2 + 3 m = 330 : 3

2 + 3 × m = 110

3 × m = 110 - 2

3 × m = 108

m = 108 : 3

m = 36 → numarul, aflat prin metoda mersului invers