Question

cum se rezolva ex: {[(280-y):3+10]×5-20}:8=60

Answer 1

{[(280-y):3+10]×5-20}:8=60

[(280-y):3+10]×5-20=60*8

[(280-y):3+10]×5-20=480

[(280-y):3+10]×5=480+20

[(280-y):3+10]×5=500

(280-y):3+10=500/5

(280-y):3+10=100

(280-y):3=100-10

(280-y):3=90

280-y=90*3

280-y=270

-y=270-280

-y=-10

y=10