Question

Cum se rezolva ex: 3×25:{5×6-[6×4:(10×2-12:n×3)-2]:2}+7=10

Answer 1

3×25:{5×6-[6×4:(10×2-12:n×3)-2]:2}+7=10
3×25:{30-[6×4:(20-12:n×3)-2]:2}=10-7=3
25:{30-[6×4:(20-12:n×3)-2]:2}=3:3=1
30-[6×4:(20-12:n×3)-2]:2 =25:1=25
[6×4:(20-12:n×3)-2]:2 =30-25=5
6×4:(20-12:n×3)-2 = 5×2=10
6×4:(20-12:n×3) = 10+2=12
4:(20-12:n×3) =12:6=2
20-12:n×3 = 4:2=2
12:n×3 = 20-2=18
12:n=18:3 =6
12:n=6
n=12:6
n=2 (am rezolvat prin metoda mersului invers)

Succes ☆