Question

Cum se rezolva ex 3?
Coroană!

Answer 1

   
[tex]\displaystyle\\ \frac{x+2}{x-3}=\frac{x-3+3+2}{x-3}=\frac{x-3+5}{x-3}=\\\\ =\frac{x-3}{x-3}+\frac{5}{x-3}=\boxed{1+\frac{5}{x-3}}\\\\ 1\in\mathbb{Z}\\ 5~\vdots~(x-3)\\\\ D_5=\{-5;~-1;~1;~5\} \\\\ x-3=-5~\Longrightarrow~x=-5+3~\Longrightarrow~x=\boxed{-2}\\ x-3=-1~\Longrightarrow~x=-1+3~\Longrightarrow~x=\boxed{2}\\ x-3=1~\Longrightarrow~x=1+3~\Longrightarrow~x=\boxed{4}\\ x-3=5~\Longrightarrow~x=5+3~\Longrightarrow~x=\boxed{8}\\\\ \boxed{\bf A=\{-2;~2;~4;~8\} }\\ \boxed{\bf\text{\bf Card}~A=4}[/tex]