Question

cum se rezolva exercitii de genul:    (2x-3)+4(4x+7)-48=3(2x+1)+4(x+3)+30

Answer 1

(2x-3)+4(4x+7)-48=3(2x+1)+4(x+3)+30
2x-3+16x+28-48=6x+3+4x+12+30
2x+16x-6x-4x=30+12+3+48-28+3
12x-4x=45+48-28+3
8x=68
x=68/8=8,5

Answer 2

Sunt simple, uite, poate o sa intelegi ceva, iti fac pe lung.
(2x-3)+4(4x+7)-48=3(2x+1)+4(x+3)+30
2x−3+4(4x+7)−48=6x+3+4(x+3)+30
2x−3+4(4x+7)−48=10x+3+12+30
2x−3+4(4x+7)−48=10x+15+30
2x−3+4(4x+7)−48=10x+45
2x−3+16x+28−48=10x+45
18x−3+28−48=10x+45
18x+25−48=10x+45
18x−23=10x+45
18x−23−10x=45
8x−23=45
8x=23+45
8x=68
x=17/2