Question

Cum se rezolvă exercițiul? :(​

Answer 1

$f(x) = x^2-x+2\\f(-x) = 3x+m\Rightarrow (-x)^2- (-x) + 2 = 3x+m\\x^2+x+2 = 3x+m\\x^2 -2x+2-m = 0\\\Delta = 4-4(2-m) = -4+4m\\\text{solu\c tie unic\u a} \Leftrightarrow \Delta = 0\Leftrightarrow -4+4m = 0\Rightarrow m= 1$