Question

Cum se rezolva expresia? E(x) trebuie sa dea 1 la final.

Answer 1

E(x) = 1;
E(x) $= ( \frac{x - 2}{ x^{2} - 4} * \frac{5x + 10}{x - 3} + 1) * \frac{x - 3}{x + 2}$
$( \frac{x - 2}{ (x+2)(x-2)} * \frac{5x + 10}{x - 3} + 1) * \frac{x - 3}{x + 2} =1$
$( \frac{1}{(x+2)} * \frac{5x + 10}{x - 3} + 1) * \frac{x - 3}{x + 2} = 1$
$\frac{(5x + 10) * (x - 3)}{(x+2)(x+2)(x-3)} + \frac{x - 3}{x + 2} = 1$
$\frac{5x + 10}{ x^{2} + 4x+4 } + \frac{x - 3}{x + 2} = 1$
De aici e gresit.. scuze
$\frac{6x + 7}{ x^{2} + 5x + 6 } = 1$
6x + 7 = x² + 5x + 6;
x + 1 = x²;
x² = x + 1;
x * x = x + 1;

Nu am putut afla x-ul final, dar sper că te-a ajutat.
Edit: x = ~1,6;

Answer 2

Hai ,poftim rezolvare mai precisa ;)succes !!!coronita !!!