Question

cum se rezolva g) si h)?

Answer 1

[tex]g) log_5 (2x-5)+log_5(2x-1)=1 \\ log_5(2x-5)(2x-1)=log_55 \\ (2x-5)(2x-1)=5 \\ 4 x^{2} -2x-10x+5=5 \\ 4 x^{2} -12x+5-5=0 \\ 4 x^{2} -12x=0|:4 \\ x^{2} -3x=0 \\ x(x-3)=0 \\ x=0 \ sau \ x-3=0 =\ \textgreater \ x=3[/tex]
S={0, 3}
[tex]log_3x+log_9x+log_{27}x= \frac{11}{2} \\ log_3x+log_{3^2}x+log_{3^3}x= \frac{11}{2} \\ log_3x+ \frac{1}{2}log_3x+ \frac{1}{3}log_3x= \frac{11}{2} \\ [/tex]