Question

Cum se rezolva problema 25

Answer 1

S=suma totala
I nepot =( 1/3)*S+32
R1 - restul dupa ce acesta isi primeste suma
R1=S-[(1/3)S+32]       pun fractia in () ca sa intelegi ca nu 3 se inmulteste cu S
R1=(2S-93)/3
al II-lea nepot = (1/3)R1+32= (4S-480)/9
R2 - restul dupa ce si al doilea nepot primeste banii
R2=R1-II nepot= (4S-480)/9
al III-lea nepot = (1/3)R2+32=(4S+384)/27
R3- restul dupa ce al III-le nepot primeste banii = 0
R3=R2-III nepot = (8S-1824)/27
R3=0 ==> 8S-1824=0 ==> S=228 lei

Verificare :

I n = (1/3)*228+32=76+32=108    R1=120
II n =(1/3)*120+32=40+32=72      R2=48
III n=48

I n + II n + III n = 108+72+48=228 lei