Question

Cum se rezolva problema:Determinati numerele a;b si c invers proportionale cu numerele 2;4;8 stiind ca a+d+c=14

Answer 1

a+b+c= 14
a /1/2 = b / 1/4= c /1/8 =k
a 1/2= k ⇒ a = k/2
b /1/4 =k ⇒ b=k/4
c /1/8=k ⇒ c=k/8
k/2+k/4+k/8= 14
aducem la acelasi numitor
4k+ 2k+k= 14x8
7k=112
k=16
a= k/2 
a= 16/2
a=8
b=16/4
b=4
c=16/8
c=2
V: a+b+c= 8+4+2=14(adevarat)