Question

Cum se rezolva radical din 2 la 7- 2 la 6? (Totul sub radical)

Answer 1

$\sqrt{ 2^{7}- 2^{6} } = \sqrt{ 2^{2}* 2^{2}* 2^{2}*2 - 2^{2}* 2^{2} * 2^{2} } =2*2*2* \sqrt{2} -2*2*2=$
$8 \sqrt{2} -8=8( \sqrt{2} -1)$