Question

cum se rezolva???(urgent)

Answer 1

     
[tex]\displaystyle E1) \\ a) \\ 3+x+2i =4+(7+5y)i \\ 3+x=4~~ \Longrightarrow ~~ x=4-3=\boxed{1} \\ 7+5y=2~~ \Longrightarrow ~~ y= \frac{2-7}{5} =\frac{-5}{5} =\boxed{-1} \\ \\ b) \\ x=\boxed{1} \\ -7=-(4-y) \\ -7 = -4+y \\ y = -7+4 = \boxed{-3}[/tex]

[tex]\displaystyle c) \\ (3x-2y)-(x-7y)i=-1-(y-4)i \\ 3x-2y=-1 \\ x-7y=y-4 \\ ------- \\ 3x-2y=-1 \\ x-8y= -4 ~~~~~~~ \Longrightarrow~~~x=8y-4 \\ ------- \\ 3(8y-4)-2y=-1 \\ 24y-12-2y=-1 \\ 22y=11 \\ y= \frac{11}{22} =\boxed{ \frac{1}{2} } \\ x=8y-4 = 8 \times \frac{1}{2} -4=4-4 =\boxed{0}[/tex]

[tex]\displaystyle d) \\ \frac{x}{3}- \frac{y}{2}= \frac{1}{6} \\ -(x-y)=(x+1) \\ --------- \\ 2x-3y=1 \\ -2x+y=1 \\ \text{--------------------- adunam fractiile} \\ -2y=2 ~~~\Longrightarrow~~~y= \frac{2}{-2} =\boxed{-1} \\ 2x-3 \times (-1) =1 \\ 2x-3=1 \\ 2x=-2~~~\Longrightarrow~~~x= \frac{-2}{2} =\boxed{-1} [/tex]