Question

Cum se rezolva urmatoarea ecuatie de gradul 2 :
xla a patra +15xla a doua +50 = 0
As vrea o rezolvare detaliat multumesc!

Answer 1

x^4+15x²+50=0
notam x²=t
t²+15t+50=0
a=1
b=15
c=50
Δ=b²-4ac=(15)²-4··1·50=225-20=25
t1=(-b+√Δ)/2a=(-15+5)/2=-10/2=-5
t2=(-15-5)/2=-20/2=-10
x²=-5
x1=√-5=5i
x2=-√-5=-5i
x²=-10
x3=√-10=10i
x4=-√-10=-10i
S={-10i,-5i,5i,10i}