Question

Cum se rezolva urmatorul exercitiu.
$\lim_{x \to \infty} 2 \sqrt{x+1} / \sqrt{3+x}$
Cat mai explicit va rog !

Answer 1

$\lim_{x \to \infty} \frac{2 \sqrt{x+1} }{ \sqrt{3+x} }= \lim_{x \to \infty} \frac{2 \sqrt{x} \sqrt{1+ \frac{1}{x} } }{ \sqrt{x} \sqrt{ \frac{3}{x}+ 1} }=2 \frac{ \sqrt{1+0} }{ \sqrt{ \sqrt{0+1} } }=2$