Question

cum se rezolva x-y=12 daca z=10 xz-yz

Answer 1

x-y=12
z=10
xz-yz=z(x-y)=10*12=120

Answer 2

$x-y=12 \\ z=10 \\ xz-yz=z(x-y)=10 \cdot 12=120 \\ \boxed{xz-yz=120}$