Question

Cum simplific cu numarul x+1 raportul x la a doua + 3x +2
x la a doua + 2x +1

Answer 1

$\frac{x^2+3x+2}{x^2+2x+1}= \frac{x^2+x+2x+2}{x^2+x+x+1}= \frac{(x^2+x)+(2x+2)}{(x^2+x)+(x+1)}= \frac{x(x+1)+2(x+1)}{x(x+1)+(x+1)}= \frac{(x+2)(x+1)}{(x+1)(x+1)}=$ $= \frac{x+2}{x+1}$