Question

d) (1+2+…+20):14 <\> 1^2+2^2
e) (6+6:6)^6-6-6^6-6 > 6

Va rog mult dau coroana

Answer 1

d) (1+2+...+20):14 > 1²+2²

=20×19:2:14 > 1+4

=10×19:14 > 5

= 190:14 >5

=190/14 > 5/1

=190/14 > 70/14

=190 > 70

( semnul "/" înseamnă "supra" sau "fracție")

e) (6+6:6)⁶ -6-6⁶-6 >6

=(6+1)⁶-6-6⁶-6 > 6

=6⁶+1⁶-6-6⁶-6 > 6

=(6⁶-6⁶) +1-6-6 > 6

= 0+1-6-6 >6

=1-6-6> 6

= -5-6 > 6

= -11 > 6 Fals