Question

d) [493: 17 - (128 : 2 la puterea 3 + 224:8): 22] : 27 - 1. vă rog! ​

Answer 1

Salut!:)

[493: 17 - (128 : 2³+ 224:8): 22] : 27 - 1=

[29-(128:8+28):22]:27-1=

[29-(16+28):22]:27-1=

(29-44:22):27-1=

(29-2):27-1=

27:27-1=1-1=0

Succes!

Answer 2

$[493:17-(128:2^3+224:8):22]:27-1= \\ =[29-(128:8+28):22]:27-1 = \\ =[29-(16+28):22]:27-1= \\ = (29-44:22):27-1=\\=(29-2):27-1=\\=27:27-1=\\=1-1= \boxed{0}$