Question

Dacă 2^29 x 5^22= x^2 atunci numărul natural x este egal cu.........
V@ rog repede dau coroana si follow repedeeeee

Answer 1

$2^{29}*5^{22}=x^2\\2^7*2^{22}*5^{22}=x^2\\2^7*(2*5)^{22}=x^2\\2^7*10^{22}=x^2\\x^2=2^7*10^{22}\\x^2=128*10^{22}\\x=\sqrt{128*10^{22}} \\x=8\sqrt{2} *10^{11}\\\\x_1=8*10^{11}\sqrt{2} \\x_2=-8*10^{11}\sqrt{2}$

Answer 2

Răspuns:

Explicație pas cu pas:

2^7 * 10^22 = x^2

2 * 2^6 * 10^22 = x^2

2^6 * 10^22 = (x^2)/2

(2^3 * 10^11)^2 = (x/V2)^2

x = V2((2^3 * 10^11)^2 )

V = radical