Question

daca (2×9)35=235×3a ,atunci determinati valoarea numarului natural a

Answer 1

(2×9)35=235×3a
18×35=235×3a
630=705a
a=630/705=126/141=42/47

Answer 2

(2x9)35=235x3a
18x35=235x3a
630=235x3a
$\frac{630}{3}$=235a
210=235a
a=$\frac{235}{210}$
a=$\frac{47}{42}$