Question

Dacă 27:(26+(6x5-7xa):9) egal 1 află valoarea lui a

Answer 1

27:[26+(6x5-7xa):9] =1
26+(30-7xa):9=27:1
26+(30-7xa):9=27
(30-7xa):9=27-26
(30-7xa):9=1
30-7xa=1x9
7xa=30-9
7xa=21
a=21:7
a=3

Answer 2

27:[26+(6x5-7xa):9]=1
26 + (30-7×a):9=27×1
26 + (30-7×a):9=27
(30-7×a):9 = 27-26
(30-7×a):9 =1
30-7×a = 9×1
30-7×a = 9
7× a = 30-9
7× a = 21
a = 21:7
a = 3