Question

Daca (3^11)^2^3+(3^3)^33+(27^3)^11*x=9^50+81^25+243^20 atunci valoarea numărului x este:.

Answer 1

Răspuns:

(3^11)^3^2+(3^3)^33+(27^3)^11•x=9^50+81^25+243^20

3¹¹ˣ⁹+3³ˣ³³+27³ˣ¹¹·x=(3²)⁵⁰+(3⁴)²⁵+(3⁵)²⁰

3⁹⁹+3⁹⁹+(3³)³³·x=3¹⁰⁰+3¹⁰⁰+3¹⁰⁰

dam factor comun 3⁹⁹si 3¹⁰⁰

3⁹⁹+3⁹⁹+3⁹⁹·x=3·3¹⁰⁰

3⁹⁹⁺¹·x=3¹⁰⁰⁺¹

x=3¹⁰¹:3¹⁰⁰

x=3¹⁰¹⁻¹⁰⁰

x=3¹

x=3