Question

Daca 5+[28+4×(1^5+2x)]:10^2=7,atunci x=?
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Answer 1

Răspuns:

5+[28+4×(1^5+2x)]:10^2=7

5+[28+4×(1+2x)]÷100=7

5+(28+4+8x)÷100=7

5+(32+8x)÷100=7

5+32+8x/100=7

5+4(8+2x)/100=7

5+8+2x/25=7

125+8+2x=175

133+2x=175

2x=175-133

2x=42

x=42/2

x=21