Question

Daca a^-1=2 si b^-3=-8, atunci a+b=?

Answer 1

$x {}^{ - 1 } = \frac{1}{x} \\ \\ \frac{1}{x} = 2 \\ \\ 2x = 1 \\ \\ x = 0.5$

Și

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$y {}^{ - 3} = \frac{1}{y {}^{3} } \\ \\ \frac{1}{y {}^{3} } = - 8 \\ \\ - 8y {}^{3} = 1 \\ \\ y {}^{3} = - \frac{1}{8} \\ \\ y = - \frac{1}{2}$

Atunci:

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$x + y = \frac{1}{2} - \frac{1}{2} = 0$