Question

Daca: a=1000-[(4×105-30):3-30] b=(84+84:4)×2 c=(6×6:6+6×6-6)-(3×3:3-3:3+3) d=a+b+c calculează: a)d-a+2c; b) (b-c)×8+c×1000; c) (4c2d)-(2c+2b)​

Answer 1

Răspuns:

a=1000-[(4×105-30):3-30]

a=1000-[(420-30):3-30]

a=1000-(390:3-30)

a=1000-(130-30)

a=1000-100

a=900

b=(84+84:4)×2

b=(84+21)×2

b=105×2

b=210

c=(6×6:6+6×6-6)-(3×3:3-3:3+3)

c=(36:6+36-6)-(9:3-1+3)

c=(6+36-6)-(3-1+3)

c=(42-6)-(2+3)

c=36-5

c=31

d=a+b+c

d=900+210+31

d=1 141

a)

d-a+2c=

1 141-900+2×31=

241+62=

303

b)

(b-c)×8+c×1 000=

(210-31)×8+31×1 000=

179×8+31×1 000=

1 432+31 000=

32 432

c)

(4c2d)-(2c+2b)=

??? ce semn este intre 4c si 2d?