Question

Daca a+2b=39 ; b+3c=60 Calculati: a) a+3b+3c b)2a+5b+3c c) a+4b+6c d) 3a+8b+6c​ Calculați rapid va rog!!!!

Answer 1

Răspuns:

a) 99;  b) 138;  c) 159;  d) 237.

Explicație pas cu pas:

Se dă:  a+2b=39,  b+3c=60

a) a+3b+3c=(a+2b)+(b+3c)=39+60=99.

b) 2a+5b+3c=2*(a+2b)+(b+3c)=2*39+60=78+60=138.

c) a+4b+6c=(a+2b)+2(b+3c)=39+2*60=39+120=159.

d) 3a+8b+6c=3*(a+2b)+2*(b+3c)=3*39+2*60=117+120=237.

Answer 2

Explicație pas cu pas:

a)

(a+2b)+(b+3c)=a+3b+3c=39+60=99

b)

(a+2b)+(a+2b)+(b+3c)=

39+39+60=78+60=138

c)

(a+2b)+ (b+3c)+(b+3c)=

39+60+60=39+120=159

d)

3(a+2b)+2(b+3c)

3a+6b+2b+6c=

3a+8b+6c=

3*39+2*60=

117+120=237