Question

Daca a+2b+3c supra 3a+b+2c=3 supra 2, atunci a supra b=...

Answer 1

$\dfrac{a+2b+3c}{3a+b+2c} = \dfrac{3}{2} \\ \\ 2(a+2b+3c) = 3(3a+b+2c) \\ 2a+4b+6c = 9a+3b+6c \\ 2a+4b = 9a+3b \\ 7a = b \\ \\\Rightarrow \boxed{\dfrac{a}{b} = \dfrac{1}{7}}$