Question

Dacă a=3×3+2×4×[7+6×(2×10-3)-2×1]-1000÷10 și b=9+[7+3×(12-7)]÷2-5×2, atunci (a+b)÷2este=cu:

Answer 1

a=3×3+2×4×[7+6×(2×10-3)-2×1]-1000÷10
a=9+8×[7+6×(20-3)-2]-100
a=9+8×(7+6×17-2)-100
a=9+8x(7+102-2)-100
a=9+8x107-100
a=9+856-100
a=765

b=9+[7+3×(12-7)]÷2-5×2
b=9+(7+3×5)÷2-10
b=9+(7+15):2-10
b=9+22:2-10
b=9+11-10
b=10

(a+b):2=(765+10):2=775:2=387,5