Question

Daca :
a=64+(100-9×9-5×2)
b=37+(45-6×6:6)
c=23+(27:9-24:8)
Află:2a+3b-4c
Acum dau coroana SI ex 5 please

Answer 1

a=64+(100-9×9-5×2)
a=64+(100-81-10)
a=64+9
a=73
b=37+(45-6×6:6)
b=37+(45-6)
b=37+39
b=76
c=23+(27:9-24:8)
c=23+(3-3)
c=23+0
c=23
2×73+3×76-23×4=

R:282

Sper că te-am ajutat !!(plz coroană)

Answer 2

a = 64 + ( 100 - 9 × 9 - 5 × 2)

a = 64 + ( 100 - 81 - 10 )

a = 64 + ( 19 - 10 )

a = 64 + 9

a = 73

_____________________

b = 37 + ( 45 - 6 × 6 : 6)

b - 37 + ( 45 - 36 : 6 )

b = 37 + ( 45 - 6)

b = 37 + 39

b = 76

______________________

c = 23 + ( 27 : 9 - 24 : 8 )

c = 23 + ( 3 - 3)

c = 23 + 0

c = 23

________________________

2 a + 3 b - 4 c = 2 × 73 + 3 ×76 - 4 × 23 = 146 + 228 - 92 = 374 - 92 = 282