Question

Daca a=7-4√3 si b=7+4√3 atunci calculati media aritmetica si medi geometrica a numerelor a si b Multumesc!

Answer 1

[tex]Ma= \frac{7-4 \sqrt{3}+7+4 \sqrt{3} }{2} = \frac{14}{2} =7 \\ Mg= \sqrt{(7-4 \sqrt{3})(7+4 \sqrt{3})} =\sqrt{7^{2}-(4 \sqrt{3})^{2}}= \sqrt{49-48} = \sqrt{1} =1[/tex]