Question

daca a+b=10 si b+c=19 calculati a+2b+c;3a+5b+2c;4a+9b+5c

Answer 1

a+b = 10
b+c = 19

a+2b+c = a+b+b+c = (a+b)+(b+c) = 10+19 = 29
3a+5b+2c = 3a+3b+2b+2c = 3(a+b)+2(b+c) = 3x10 + 2x19 = 30+38 = 68
4a+9b+5c = 4a+4b+5b+5c = 4(a+b)+5(b+c) = 4x10 + 5x19 = 40+95 = 135

Sper ca te-am ajutat!