Question

DACA A+B=3VIRGULA1 SI B+C=4VIRGULA5 ATUNCI CALCULATI [A+B]X{2A+3B+C}? DACA A+B=0VIRGULA5 SI B+C=0VIRGULA7 ATUNCI CALCULATI {A+2B+C}X{C-A}? DACA A+B=14VIRGULA35 SI A+C=9VIRGULA12 ATUNCI CALCULATI{2A+B+C}X{B-C}?

Answer 1

a+b=3,1
b+c=4,5
(a+b)* (2a+3b+c)=3,1*(2a+3b+c)=6,2a+9,3b+3,1c
a+b=0,5
b+c=0,7
(a+2b+c)*(c-a)=(0,5+0,7)*(c-a)=3,5c-3,5a
a+b=14,35
a+c=9,12
(2a+b+c)*(b-c)=(14,35+9,12)*(b-c)=23,47b-23,47c