Question

Daca a,b,c sunt numere naturale si a+b+c=18 ,iar 2a+b+2c=25 atunci calculati (a+c)×(3a+2b+3c)!

Ajutorrr!!

Answer 1

a+b+c=182a+b+2c=25  2a+b+2c-(a+b+c)=25-18a+c=7  b=18-7=11
(a+c)(3a+2b+3c)=7(3x7+2x11)=7(21+22)=7x43=301

Answer 2

a+b+c=18
2a+b+2c=25
(a+c)(3a+2b+3c)=?
a+b+c+2a+b+2c=18+25
3a+2b+3c=43
2a+b+2c-(a+b+c)=25-18
2a+b+2c-a-b-c=7
a+c=7
(a+c)(3a+2b+3c)=7*43=301