Question

daca a si b sunt numere naturale astfel incat 3×a +2×b =2020,calculeaza : a)6×a+4×b. b) 9×a+6×b. c) 12×a+9+8×b. va rog ma ajutati????

Answer 1

3×a+2×b=2020

a)6×a+4×b=

2(3×a+2×b)=

2×2020=

4040

b)9×a+6×b=

3(3×a+2×b)=

3×2020=

6060

c)12×a+9+8×b=

4(3×a+2×b)+9=

4×2020+9=

8080+9=

8089