Question

Daca AOB,BOC si COA sunt unghiuri in jurul punctului O,m(<AOB)=100° si m(<BOC)=m(<COA)+50°,afla m(<BOC) si m(<COA).

Answer 1

BOC+COA=360-100=260

BOC=COA+50

COA+50+COA=260
2COA=210
COA=105°
BOC=260-105
BOC=155°

Answer 2

m(<AOB)+m(<BOC)+m(<COA)=360°
unghiuri in jurul unui punct
100°+m(<COA)+50°+m(<COA)=360
2m(<COA)=360°-50°-100°
2m(<COA)=210°
m(<COA)=210°:2
m(<COA)=105°
m(<BOC)=155°