Question

daca arajam niste portocale cate 5 raman 3 si daca le aranjam cate 7 raman 5.Cate portocale sunt ?

Answer 1

Fie x = nr de portocale

x:5=c1 rest 3
x:7=c2 rest 5

x=?
D=C•Î+R

x=5c1+3 => x=5c1+5-2 => x=5(c1+2) => (x+2) divizibil cu 5
x=7c2+5 => x=7c2+7-2 => x=7(c2+2) => (x+2) divizibil cu 7
=> x=c.m.m.m.c al nunerelor 5 si 7

5=5
7=7
——
[5;7]=5•7=35

x+2=35
x=35-2
x=33