Question

dacă axb=100,cxa=75,calculeza:a(b+c):5 și a(b-c):5

Answer 1

$\frac{a(b+c)}{5} = \frac{ab+ac}{5} = \frac{100+75}{5} = \frac{175}{5} =35$

$\frac{a(b-c)}{5} = \frac{ab-ac}{5} = \frac{100-75}{5} = \frac{25}{5} =5$